-[6z-(12z+2)]=2+(5z+0)

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Solution for -[6z-(12z+2)]=2+(5z+0) equation:


Simplifying
-1[6z + -1(12z + 2)] = 2 + (5z + 0)

Reorder the terms:
-1[6z + -1(2 + 12z)] = 2 + (5z + 0)
-1[6z + (2 * -1 + 12z * -1)] = 2 + (5z + 0)
-1[6z + (-2 + -12z)] = 2 + (5z + 0)

Reorder the terms:
-1[-2 + 6z + -12z] = 2 + (5z + 0)

Combine like terms: 6z + -12z = -6z
-1[-2 + -6z] = 2 + (5z + 0)
[-2 * -1 + -6z * -1] = 2 + (5z + 0)
[2 + 6z] = 2 + (5z + 0)

Reorder the terms:
2 + 6z = 2 + (0 + 5z)
Remove the zero:
2 + 6z = 2 + (5z)
2 + 6z = 2 + (5z)

Add '-2' to each side of the equation.
2 + -2 + 6z = 2 + -2 + (5z)

Combine like terms: 2 + -2 = 0
0 + 6z = 2 + -2 + (5z)
6z = 2 + -2 + (5z)

Combine like terms: 2 + -2 = 0
6z = 0 + (5z)
6z = (5z)

Solving
6z = (5z)

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '(-5z)' to each side of the equation.
6z + (-5z) = (5z) + (-5z)

Combine like terms: 6z + (-5z) = 1z
1z = (5z) + (-5z)

Combine like terms: (5z) + (-5z) = 0
1z = 0

Divide each side by '1'.
z = 0

Simplifying
z = 0

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